Jonathan Kalil Eliminated in 4th Place (ZAR291,600)
Level 26
: Blinds 40,000/80,000, 80,000 ante
Soon after their previous encounter, Jonathan Kalil limped the small blind and Stephen Courtney moved all-in for Kalil to call for 2,050,000.
Jonathan Kalil: A♦10♦ 
Stephen Courtney: 7♣7♠
The 10♠4♣2♣ flop improved Kalil but the 7♦ turn locked up the hand for Courtney, who then even made quads with the 7♥ river to score the elimination in style. Kalil's run comes with a payday of ZAR291,600 ($16,038).
| Player | Chips | Progress |
|---|---|---|
|
4,500,000
2,100,000
|
2,100,000 |
|
Busted |